3[y-2]+x=1

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Solution for 3[y-2]+x=1 equation:


Simplifying
3[y + -2] + x = 1

Reorder the terms:
3[-2 + y] + x = 1
[-2 * 3 + y * 3] + x = 1
[-6 + 3y] + x = 1

Reorder the terms:
-6 + x + 3y = 1

Solving
-6 + x + 3y = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + x + 6 + 3y = 1 + 6

Reorder the terms:
-6 + 6 + x + 3y = 1 + 6

Combine like terms: -6 + 6 = 0
0 + x + 3y = 1 + 6
x + 3y = 1 + 6

Combine like terms: 1 + 6 = 7
x + 3y = 7

Add '-3y' to each side of the equation.
x + 3y + -3y = 7 + -3y

Combine like terms: 3y + -3y = 0
x + 0 = 7 + -3y
x = 7 + -3y

Simplifying
x = 7 + -3y

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